| Ch 2-1: Velocity
The position of an object is how far away it is from
a reference point (frame of reference)
Scalar - just magnitude (how much)
Vector - magnitude and direction (how much and which
way)
Displacement is the change in position
(final position
original position)
Displacement is a vector quantity and can be positive
or negative.
Average velocity is the displacement (change in position)
divided by the change
in time (time interval).
Velocity is how fast and in what direction. Speed
is only how fast.
v = d/t {which also gives us: t= d/v and d = vt
This equation only works for constant or average velocity.
For constant/uniform velocity, a position-time graph
yields a straight line. The slope of that line is equal to the velocity.
Instantaneous velocity is the velocity at a specific
moment in time. If there is acceleration, instantaneous velocity
is not the same as average velocity.
Ch 2-2: Acceleration
Acceleration is the change in velocity divided by the
change in time.
Acceleration can be determined graphically from a velocity-time
graph.
If the velocity-time graph is a straight line, then
the acceleration is constant (uniform) and is equal to the slope of the
line.
For uniform acceleration, the velocity-time graph is
linear.
Ch 2-2 contains 4 basic equations that use 5 variables.
The 5 variables are:
a ... which stands for
acceleration; for free-falling objects, a = g = -9.8 m/s/s
t ... which stands for
time, or the time interval (change in time)
d ... which stands for
displacement, or change in position
vi ...
which stands for the initial velocity at the beginning of the time period
in question
vf ...
which stands for the final velocity at the end of the time period in question
The 4 equations are given below. Each uses 4 variables.
The problems will contain 3 known/given variables and 1 unknown variable.
You need to pick the equation that contains those 4 (3 known / 1 unknown)
variables. You may have to rearrange the equation so that the unknown is
by itself on one side of the equation.
Equation
Variables
vf = vi +
at vf
, vi, a, t
d = ½ (vf
+ vi) t d, vf, vi,
t
d = vit + ½at2
d, vi, t, a
vf2 = vi2
+ 2ad vf,
vi, a, d
Steps to solving a problem.
1) Read the problem.
2) Identify the given variables and the unknown
variable it is asking for.
3) Select the proper equation to use.
4) If the unknown is not by itself on one side
(preferably the left), then you should rearrange the equation to make it
so. It is possible to put in the numbers and then rearrange it, but this
will turn out to be more difficult in the long run.
5) Do the math required to solve for the unknown.
6) If there is a second part to the problem, you
can probably use any of the remaining three equations, since you will now
know 4 of the 5 variables.
7) Check to make sure your answer is reasonable
(i.e. if you're 3 given variable are in single digits, an answer in the
millions might be a sign that something is wrong). Also, check to see that
you have the correct units (i.e. if you are finding a velocity and your
answer is in meters, something is wrong somewhere).
Ch 2-3: Free-falling
The acceleration of gravity near the earth is -9.80 m/s/s.
By making it negative, you are saying that upward motion is the positive
direction, and downward is negative. |